16(v+2)-4v=4(3v+3)-21

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Solution for 16(v+2)-4v=4(3v+3)-21 equation: 


Simplifying
16(v + 2) + -4v = 4(3v + 3) + -21

Reorder the terms:
16(2 + v) + -4v = 4(3v + 3) + -21
(2 * 16 + v * 16) + -4v = 4(3v + 3) + -21
(32 + 16v) + -4v = 4(3v + 3) + -21

Combine like terms: 16v + -4v = 12v
32 + 12v = 4(3v + 3) + -21

Reorder the terms:
32 + 12v = 4(3 + 3v) + -21
32 + 12v = (3 * 4 + 3v * 4) + -21
32 + 12v = (12 + 12v) + -21

Reorder the terms:
32 + 12v = 12 + -21 + 12v

Combine like terms: 12 + -21 = -9
32 + 12v = -9 + 12v

Add '-12v' to each side of the equation.
32 + 12v + -12v = -9 + 12v + -12v

Combine like terms: 12v + -12v = 0
32 + 0 = -9 + 12v + -12v
32 = -9 + 12v + -12v

Combine like terms: 12v + -12v = 0
32 = -9 + 0
32 = -9

Solving
32 = -9

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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