16(v+2)-4v=3(4v+1)-7

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Solution for 16(v+2)-4v=3(4v+1)-7 equation: 



16(v+2)-4v=3(4v+1)-7

We move all terms to the left:

16(v+2)-4v-(3(4v+1)-7)=0

We add all the numbers together, and all the variables

-4v+16(v+2)-(3(4v+1)-7)=0

We multiply parentheses

-4v+16v-(3(4v+1)-7)+32=0



We calculate terms in parentheses: -(3(4v+1)-7), so:

3(4v+1)-7

We multiply parentheses

12v+3-7

We add all the numbers together, and all the variables

12v-4

Back to the equation:

-(12v-4)



We add all the numbers together, and all the variables

12v-(12v-4)+32=0

We get rid of parentheses

12v-12v+4+32=0

We add all the numbers together, and all the variables

36!=0

There is no solution for this equation

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