16(t-3)=8t+8t-48

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Solution for 16(t-3)=8t+8t-48 equation: 



16(t-3)=8t+8t-48

We move all terms to the left:

16(t-3)-(8t+8t-48)=0

We add all the numbers together, and all the variables

16(t-3)-(16t-48)=0

We multiply parentheses

16t-(16t-48)-48=0

We get rid of parentheses

16t-16t+48-48=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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