16(d/4-7)=128

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Solution for 16(d/4-7)=128 equation:



16(d/4-7)=128
We move all terms to the left:
16(d/4-7)-(128)=0
We multiply parentheses
16d-112-128=0
We add all the numbers together, and all the variables
16d-240=0
We move all terms containing d to the left, all other terms to the right
16d=240
d=240/16
d=15

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