16(9-c)+12c=120

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Solution for 16(9-c)+12c=120 equation: 



16(9-c)+12c=120

We move all terms to the left:

16(9-c)+12c-(120)=0

We add all the numbers together, and all the variables

16(-1c+9)+12c-120=0

We add all the numbers together, and all the variables

12c+16(-1c+9)-120=0

We multiply parentheses

12c-16c+144-120=0

We add all the numbers together, and all the variables

-4c+24=0

We move all terms containing c to the left, all other terms to the right

-4c=-24

c=-24/-4

c=+6

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