16(4-3m)=96(-m/2=1)

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Solution for 16(4-3m)=96(-m/2=1) equation: 



16(4-3m)=96(-m/2=1)

We move all terms to the left:

16(4-3m)-(96(-m/2)=0

We add all the numbers together, and all the variables

16(-3m+4)-(96(-m/2)=0

We multiply parentheses

-48m-(96(-m/2)+64=0

We multiply all the terms by the denominator


-48m*2)+64-(96(-m=0

Wy multiply elements

-96m^2=0

a = -96; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-96)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{-192}=0$

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