16(3z+1)-2=9

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Solution for 16(3z+1)-2=9 equation: 



16(3z+1)-2=9

We move all terms to the left:

16(3z+1)-2-(9)=0

We add all the numbers together, and all the variables

16(3z+1)-11=0

We multiply parentheses

48z+16-11=0

We add all the numbers together, and all the variables

48z+5=0

We move all terms containing z to the left, all other terms to the right

48z=-5

z=-5/48

z=-5/48

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