16(3y-2)=8(7y-2)

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Solution for 16(3y-2)=8(7y-2) equation: 



16(3y-2)=8(7y-2)

We move all terms to the left:

16(3y-2)-(8(7y-2))=0

We multiply parentheses

48y-(8(7y-2))-32=0



We calculate terms in parentheses: -(8(7y-2)), so:

8(7y-2)

We multiply parentheses

56y-16

Back to the equation:

-(56y-16)



We get rid of parentheses

48y-56y+16-32=0

We add all the numbers together, and all the variables

-8y-16=0

We move all terms containing y to the left, all other terms to the right

-8y=16

y=16/-8

y=-2

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