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16(3x+1)-30=3(2x-4)
We move all terms to the left:
16(3x+1)-30-(3(2x-4))=0
We multiply parentheses
48x-(3(2x-4))+16-30=0
We calculate terms in parentheses: -(3(2x-4)), so:We add all the numbers together, and all the variables
3(2x-4)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
48x-(6x-12)-14=0
We get rid of parentheses
48x-6x+12-14=0
We add all the numbers together, and all the variables
42x-2=0
We move all terms containing x to the left, all other terms to the right
42x=2
x=2/42
x=1/21
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