16(3a-5)-10(4a-8)=40

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Solution for 16(3a-5)-10(4a-8)=40 equation: 



16(3a-5)-10(4a-8)=40

We move all terms to the left:

16(3a-5)-10(4a-8)-(40)=0

We multiply parentheses

48a-40a-80+80-40=0

We add all the numbers together, and all the variables

8a-40=0

We move all terms containing a to the left, all other terms to the right

8a=40

a=40/8

a=5

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