16(2y)=3(y+6)

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Solution for 16(2y)=3(y+6) equation: 



16(2y)=3(y+6)

We move all terms to the left:

16(2y)-(3(y+6))=0



We calculate terms in parentheses: -(3(y+6)), so:

3(y+6)

We multiply parentheses

3y+18

Back to the equation:

-(3y+18)



We get rid of parentheses

162y-3y-18=0

We add all the numbers together, and all the variables

159y-18=0

We move all terms containing y to the left, all other terms to the right

159y=18

y=18/159

y=6/53

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