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((16*(2*x-6))/20)*(x-3) = 0
(16*(2*x-6)*(x-3))/20 = 0
( 16 )
16 = 0
x belongs to the empty set
( 2*x-6 )
2*x-6 = 0 // + 6
2*x = 6 // : 2
x = 6/2
x = 3
( x-3 )
x-3 = 0 // + 3
x = 3
x in { 3, 3 }
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