16(27b-31)+3(37b-8)=3+34b+26b-40

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Solution for 16(27b-31)+3(37b-8)=3+34b+26b-40 equation: 



16(27b-31)+3(37b-8)=3+34b+26b-40

We move all terms to the left:

16(27b-31)+3(37b-8)-(3+34b+26b-40)=0

We add all the numbers together, and all the variables

16(27b-31)+3(37b-8)-(60b-37)=0

We multiply parentheses

432b+111b-(60b-37)-496-24=0

We get rid of parentheses

432b+111b-60b+37-496-24=0

We add all the numbers together, and all the variables

483b-483=0

We move all terms containing b to the left, all other terms to the right

483b=483

b=483/483

b=1

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