16((2x-2)/3)=0

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Solution for 16((2x-2)/3)=0 equation: 


x in (-oo:+oo)

16*((2*x-2)/3) = 0

(16*(2*x-2))/3 = 0

( 16 )

16 = 0

x belongs to the empty set

( 2*x-2 )

2*x-2 = 0 // + 2

2*x = 2 // : 2

x = 2/2

x = 1

x = 1

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