15y-2(4y-1)=(3y-1)

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Solution for 15y-2(4y-1)=(3y-1) equation: 



15y-2(4y-1)=(3y-1)

We move all terms to the left:

15y-2(4y-1)-((3y-1))=0

We multiply parentheses

15y-8y-((3y-1))+2=0



We calculate terms in parentheses: -((3y-1)), so:

(3y-1)

We get rid of parentheses

3y-1

Back to the equation:

-(3y-1)



We add all the numbers together, and all the variables

7y-(3y-1)+2=0

We get rid of parentheses

7y-3y+1+2=0

We add all the numbers together, and all the variables

4y+3=0

We move all terms containing y to the left, all other terms to the right

4y=-3

y=-3/4

y=-3/4

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