15y-10=6y-(y+2)-(y+3)

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Solution for 15y-10=6y-(y+2)-(y+3) equation: 



15y-10=6y-(y+2)-(y+3)

We move all terms to the left:

15y-10-(6y-(y+2)-(y+3))=0



We calculate terms in parentheses: -(6y-(y+2)-(y+3)), so:

6y-(y+2)-(y+3)

We get rid of parentheses

6y-y-y-2-3

We add all the numbers together, and all the variables

4y-5

Back to the equation:

-(4y-5)



We get rid of parentheses

15y-4y+5-10=0

We add all the numbers together, and all the variables

11y-5=0

We move all terms containing y to the left, all other terms to the right

11y=5

y=5/11

y=5/11

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