15y-10=6y(y+2)+(-y+3)

Solution for 15y-10=6y(y+2)+(-y+3) equation:

15y-10=6y(y+2)+(-y+3)

We move all terms to the left:

15y-10-(6y(y+2)+(-y+3))=0

We add all the numbers together, and all the variables

15y-(6y(y+2)+(-1y+3))-10=0


We calculate terms in parentheses: -(6y(y+2)+(-1y+3)), so:

6y(y+2)+(-1y+3)

We multiply parentheses

6y^2+12y+(-1y+3)

We get rid of parentheses

6y^2+12y-1y+3

We add all the numbers together, and all the variables

6y^2+11y+3

Back to the equation:

-(6y^2+11y+3)


We get rid of parentheses

-6y^2+15y-11y-3-10=0

We add all the numbers together, and all the variables

-6y^2+4y-13=0

a = -6; b = 4; c = -13;
Δ = b2-4ac
Δ = 42-4·(-6)·(-13)
Δ = -296
Delta is less than zero, so there is no solution for the equation