15x=(5x+2)5x

Solution for 15x=(5x+2)5x equation:

15x=(5x+2)5x

We move all terms to the left:

15x-((5x+2)5x)=0


We calculate terms in parentheses: -((5x+2)5x), so:

(5x+2)5x

We multiply parentheses

25x^2+10x

Back to the equation:

-(25x^2+10x)


We get rid of parentheses

-25x^2+15x-10x=0

We add all the numbers together, and all the variables

-25x^2+5x=0

a = -25; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-25)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-25}=\frac{-10}{-50}
=1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-25}=\frac{0}{-50}
=0
$