15x2-150x+16=0

Solution for 15x2-150x+16=0 equation:

15x^2-150x+16=0

a = 15; b = -150; c = +16;
Δ = b2-4ac
Δ = -1502-4·15·16
Δ = 21540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{21540}=\sqrt{4*5385}=\sqrt{4}*\sqrt{5385}=2\sqrt{5385}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-2\sqrt{5385}}{2*15}=\frac{150-2\sqrt{5385}}{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+2\sqrt{5385}}{2*15}=\frac{150+2\sqrt{5385}}{30}
$