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15x^2-14=29x
We move all terms to the left:
15x^2-14-(29x)=0
a = 15; b = -29; c = -14;
Δ = b2-4ac
Δ = -292-4·15·(-14)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-41}{2*15}=\frac{-12}{30} =-2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+41}{2*15}=\frac{70}{30} =2+1/3 $
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