15x-2((1-20x)/3)=4

Solution for 15x-2((1-20x)/3)=4 equation:

15x-2((1-20x)/3)=4

We move all terms to the left:

15x-2((1-20x)/3)-(4)=0

We add all the numbers together, and all the variables

15x-2((-20x+1)/3)-4=0

We multiply all the terms by the denominator


15x*3)-2((-20x+1)-4*3)=0

We add all the numbers together, and all the variables

15x*3)-2((-20x+1)=0

Wy multiply elements

45x^2=0

a = 45; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·45·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{90}=0$