15x-10=6x(x+2)+(-x+24)

Solution for 15x-10=6x(x+2)+(-x+24) equation:

15x-10=6x(x+2)+(-x+24)

We move all terms to the left:

15x-10-(6x(x+2)+(-x+24))=0

We add all the numbers together, and all the variables

15x-(6x(x+2)+(-1x+24))-10=0


We calculate terms in parentheses: -(6x(x+2)+(-1x+24)), so:

6x(x+2)+(-1x+24)

We multiply parentheses

6x^2+12x+(-1x+24)

We get rid of parentheses

6x^2+12x-1x+24

We add all the numbers together, and all the variables

6x^2+11x+24

Back to the equation:

-(6x^2+11x+24)


We get rid of parentheses

-6x^2+15x-11x-24-10=0

We add all the numbers together, and all the variables

-6x^2+4x-34=0

a = -6; b = 4; c = -34;
Δ = b2-4ac
Δ = 42-4·(-6)·(-34)
Δ = -800
Delta is less than zero, so there is no solution for the equation