15x-(x+3)=28x+(x-12)

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Solution for 15x-(x+3)=28x+(x-12) equation: 



15x-(x+3)=28x+(x-12)

We move all terms to the left:

15x-(x+3)-(28x+(x-12))=0

We get rid of parentheses

15x-x-(28x+(x-12))-3=0



We calculate terms in parentheses: -(28x+(x-12)), so:

28x+(x-12)

We get rid of parentheses

28x+x-12

We add all the numbers together, and all the variables

29x-12

Back to the equation:

-(29x-12)



We add all the numbers together, and all the variables

14x-(29x-12)-3=0

We get rid of parentheses

14x-29x+12-3=0

We add all the numbers together, and all the variables

-15x+9=0

We move all terms containing x to the left, all other terms to the right

-15x=-9

x=-9/-15

x=3/5

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