15x+14=4(23x+5)15x+14=4(23x+5)

Solution for 15x+14=4(23x+5)15x+14=4(23x+5) equation:

15x+14=4(23x+5)15x+14=4(23x+5)

We move all terms to the left:

15x+14-(4(23x+5)15x+14)=0


We calculate terms in parentheses: -(4(23x+5)15x+14), so:

4(23x+5)15x+14

We multiply parentheses

1380x^2+300x+14

Back to the equation:

-(1380x^2+300x+14)


We get rid of parentheses

-1380x^2+15x-300x-14+14=0

We add all the numbers together, and all the variables

-1380x^2-285x=0

a = -1380; b = -285; c = 0;
Δ = b2-4ac
Δ = -2852-4·(-1380)·0
Δ = 81225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81225}=285$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-285)-285}{2*-1380}=\frac{0}{-2760}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-285)+285}{2*-1380}=\frac{570}{-2760}
=-19/92
$