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15x+12+3x(2x-6)=3x-(21x-1)+2

We move all terms to the left:

15x+12+3x(2x-6)-(3x-(21x-1)+2)=0

We multiply parentheses

6x^2+15x-18x-(3x-(21x-1)+2)+12=0

We calculate terms in parentheses: -(3x-(21x-1)+2), so:We add all the numbers together, and all the variables

3x-(21x-1)+2

We get rid of parentheses

3x-21x+1+2

We add all the numbers together, and all the variables

-18x+3

Back to the equation:

-(-18x+3)

6x^2-3x-(-18x+3)+12=0

We get rid of parentheses

6x^2-3x+18x-3+12=0

We add all the numbers together, and all the variables

6x^2+15x+9=0

a = 6; b = 15; c = +9;

Δ = b^{2}-4ac

Δ = 15^{2}-4·6·9

Δ = 9

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-3}{2*6}=\frac{-18}{12} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+3}{2*6}=\frac{-12}{12} =-1 $

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