15p2+80=-80p

Solution for 15p2+80=-80p equation:

15p^2+80=-80p

We move all terms to the left:

15p^2+80-(-80p)=0

We get rid of parentheses

15p^2+80p+80=0

a = 15; b = 80; c = +80;
Δ = b2-4ac
Δ = 802-4·15·80
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-40}{2*15}=\frac{-120}{30}
=-4
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+40}{2*15}=\frac{-40}{30}
=-1+1/3
$