15e+(-6e+5)-22-(-e+3)=(7e+23)-e+(3-2e)

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Solution for 15e+(-6e+5)-22-(-e+3)=(7e+23)-e+(3-2e) equation: 



15e+(-6e+5)-22-(-e+3)=(7e+23)-e+(3-2e)

We move all terms to the left:

15e+(-6e+5)-22-(-e+3)-((7e+23)-e+(3-2e))=0

We add all the numbers together, and all the variables

15e+(-6e+5)-(-1e+3)-((7e+23)-e+(-2e+3))-22=0

We get rid of parentheses

15e-6e+1e-((7e+23)-e+(-2e+3))+5-3-22=0



We calculate terms in parentheses: -((7e+23)-e+(-2e+3)), so:

(7e+23)-e+(-2e+3)

We add all the numbers together, and all the variables

-1e+(7e+23)+(-2e+3)

We get rid of parentheses

-1e+7e-2e+23+3

We add all the numbers together, and all the variables

4e+26

Back to the equation:

-(4e+26)



We add all the numbers together, and all the variables

10e-(4e+26)-20=0

We get rid of parentheses

10e-4e-26-20=0

We add all the numbers together, and all the variables

6e-46=0

We move all terms containing e to the left, all other terms to the right

6e=46

e=46/6

e=7+2/3

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