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15c+8+3=2(7c+2)
We move all terms to the left:
15c+8+3-(2(7c+2))=0
We add all the numbers together, and all the variables
15c-(2(7c+2))+11=0
We calculate terms in parentheses: -(2(7c+2)), so:We get rid of parentheses
2(7c+2)
We multiply parentheses
14c+4
Back to the equation:
-(14c+4)
15c-14c-4+11=0
We add all the numbers together, and all the variables
c+7=0
We move all terms containing c to the left, all other terms to the right
c=-7
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