15=4(2x-3)+5

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Solution for 15=4(2x-3)+5 equation:



15=4(2x-3)+5
We move all terms to the left:
15-(4(2x-3)+5)=0
We calculate terms in parentheses: -(4(2x-3)+5), so:
4(2x-3)+5
We multiply parentheses
8x-12+5
We add all the numbers together, and all the variables
8x-7
Back to the equation:
-(8x-7)
We get rid of parentheses
-8x+7+15=0
We add all the numbers together, and all the variables
-8x+22=0
We move all terms containing x to the left, all other terms to the right
-8x=-22
x=-22/-8
x=2+3/4

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