15=3(c-2)+6

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Solution for 15=3(c-2)+6 equation: 



15=3(c-2)+6

We move all terms to the left:

15-(3(c-2)+6)=0



We calculate terms in parentheses: -(3(c-2)+6), so:

3(c-2)+6

We multiply parentheses

3c-6+6

We add all the numbers together, and all the variables

3c

Back to the equation:

-(3c)



We move all terms containing c to the left, all other terms to the right

-3c=-15

c=-15/-3

c=+5

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