15=2(x-3)+6

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Solution for 15=2(x-3)+6 equation: 



15=2(x-3)+6

We move all terms to the left:

15-(2(x-3)+6)=0



We calculate terms in parentheses: -(2(x-3)+6), so:

2(x-3)+6

We multiply parentheses

2x-6+6

We add all the numbers together, and all the variables

2x

Back to the equation:

-(2x)



We move all terms containing x to the left, all other terms to the right

-2x=-15

x=-15/-2

x=7+1/2

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