15=(x/2)+5

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Solution for 15=(x/2)+5 equation: 



15=(x/2)+5

We move all terms to the left:

15-((x/2)+5)=0

We add all the numbers together, and all the variables

-((+x/2)+5)+15=0

We multiply all the terms by the denominator


-((+x+15*2)+5)=0



We calculate terms in parentheses: -((+x+15*2)+5), so:

(+x+15*2)+5

We add all the numbers together, and all the variables

(x+30)+5

We get rid of parentheses

x+30+5

We add all the numbers together, and all the variables

x+35

Back to the equation:

-(x+35)



We get rid of parentheses

-x-35=0

We add all the numbers together, and all the variables

-1x-35=0

We move all terms containing x to the left, all other terms to the right

-x=35

x=35/-1

x=-35

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