15=(-1/2)(-12x+2)

Solution for 15=(-1/2)(-12x+2) equation:

15=(-1/2)(-12x+2)

We move all terms to the left:

15-((-1/2)(-12x+2))=0


Domain of the equation: 2)(-12x+2))!=0

x∈R


We multiply parentheses ..

-((+12x^2-1/2*2))+15=0

We multiply all the terms by the denominator


-((+12x^2-1+15*2*2))=0


We calculate terms in parentheses: -((+12x^2-1+15*2*2)), so:

(+12x^2-1+15*2*2)

We get rid of parentheses

12x^2-1+15*2*2

We add all the numbers together, and all the variables

12x^2+59

Back to the equation:

-(12x^2+59)


We get rid of parentheses

-12x^2-59=0

a = -12; b = 0; c = -59;
Δ = b2-4ac
Δ = 02-4·(-12)·(-59)
Δ = -2832
Delta is less than zero, so there is no solution for the equation