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156=n2
We move all terms to the left:
156-(n2)=0
We add all the numbers together, and all the variables
-1n^2+156=0
a = -1; b = 0; c = +156;
Δ = b2-4ac
Δ = 02-4·(-1)·156
Δ = 624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{624}=\sqrt{16*39}=\sqrt{16}*\sqrt{39}=4\sqrt{39}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{39}}{2*-1}=\frac{0-4\sqrt{39}}{-2} =-\frac{4\sqrt{39}}{-2} =-\frac{2\sqrt{39}}{-1} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{39}}{2*-1}=\frac{0+4\sqrt{39}}{-2} =\frac{4\sqrt{39}}{-2} =\frac{2\sqrt{39}}{-1} $
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