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(2-(6*x))*(3*x+9) >= x^2-9
1*x^2-(3*x)+0*x^3-4 = 0
(1-x)*(x^2+3)^(1/2)
1*x^2-(3*x)+0*x^3-4 = 0
8*x^3-6*x^2-17*x-6;8*x^2-10*x-12
| -1y-12y+-32=-19 | | 3x=-4x-3 | | -7x+14+9x-15=2 | | 70=17x-32 | | 6+9(x-4)=10-8(x-2) | | X^2+5-21=0 | | 9x-20=3x+9 | | 3^2cosx*4^cosx=1/6 | | -3(-18x+46)=-10(-28+3x) | | (9sqrt(3))/3^n | | (2x-11)(x+6)= | | 7(2x-9)-18=15 | | 700+900+4x=750+200+7x | | -5x^4+72x^3-324x^2+432x=0 | | 3a-8b=6 | | 3(x-7)-2(x-3)=-18 | | 5/2x4/5 | | 6x+2512=25 | | 3(7-z)-31=17z-5(2+4z) | | 10x-9x=30 | | 15=3q/2-9 | | 7x-6=2x-8 | | 21x-5-13x+4=18x-3-10x+16 | | 3b-5+-b= | | =2.15(2x^2-4x-6) | | 1/3(2x-1 | | 0=3t^2-12t+2 | | -3y+12y-39=-12 | | 2z-(1+i)z=4+i | | 2.5x+3y=40 | | 1.3+0.1x=0.8 | | 15=3q-9/2 |