150x2+120x-189=3

Solution for 150x2+120x-189=3 equation:

150x^2+120x-189=3

We move all terms to the left:

150x^2+120x-189-(3)=0

We add all the numbers together, and all the variables

150x^2+120x-192=0

a = 150; b = 120; c = -192;
Δ = b2-4ac
Δ = 1202-4·150·(-192)
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{129600}=360$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-360}{2*150}=\frac{-480}{300}
=-1+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+360}{2*150}=\frac{240}{300}
=4/5
$