150=3(50+4y)+4y

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Solution for 150=3(50+4y)+4y equation: 



150=3(50+4y)+4y

We move all terms to the left:

150-(3(50+4y)+4y)=0

We add all the numbers together, and all the variables

-(3(4y+50)+4y)+150=0



We calculate terms in parentheses: -(3(4y+50)+4y), so:

3(4y+50)+4y

We add all the numbers together, and all the variables

4y+3(4y+50)

We multiply parentheses

4y+12y+150

We add all the numbers together, and all the variables

16y+150

Back to the equation:

-(16y+150)



We get rid of parentheses

-16y-150+150=0

We add all the numbers together, and all the variables

-16y=0

y=0/-16

y=0

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