150(1.15t-0.37)t=25

Solution for 150(1.15t-0.37)t=25 equation:

150(1.15t-0.37)t=25

We move all terms to the left:

150(1.15t-0.37)t-(25)=0

We multiply parentheses

150t^2-55.5t-25=0

a = 150; b = -55.5; c = -25;
Δ = b2-4ac
Δ = -55.52-4·150·(-25)
Δ = 18080.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55.5)-\sqrt{18080.25}}{2*150}=\frac{55.5-\sqrt{18080.25}}{300}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55.5)+\sqrt{18080.25}}{2*150}=\frac{55.5+\sqrt{18080.25}}{300}
$