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15/2x-6/x=2
We move all terms to the left:
15/2x-6/x-(2)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x!=0We calculate fractions
x∈R
15x/2x^2+(-12x)/2x^2-2=0
We multiply all the terms by the denominator
15x+(-12x)-2*2x^2=0
Wy multiply elements
-4x^2+15x+(-12x)=0
We get rid of parentheses
-4x^2+15x-12x=0
We add all the numbers together, and all the variables
-4x^2+3x=0
a = -4; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-4)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-4}=\frac{-6}{-8} =3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-4}=\frac{0}{-8} =0 $
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