15-8h2-2h=0

Solution for 15-8h2-2h=0 equation:

15-8h^2-2h=0

a = -8; b = -2; c = +15;
Δ = b2-4ac
Δ = -22-4·(-8)·15
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-22}{2*-8}=\frac{-20}{-16}
=1+1/4
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+22}{2*-8}=\frac{24}{-16}
=-1+1/2
$