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15-3x=5+(x/2)
We move all terms to the left:
15-3x-(5+(x/2))=0
We add all the numbers together, and all the variables
-3x-(5+(+x/2))+15=0
We multiply all the terms by the denominator
-3x*2))-(5+(+x+15*2))=0
We add all the numbers together, and all the variables
-3x*2))-(5+(x+30))=0
We add all the numbers together, and all the variables
-3x*2))-(5+(x=0
Wy multiply elements
-6x^2=0
a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-12}=0$
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