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15-3p=2/3p+5
We move all terms to the left:
15-3p-(2/3p+5)=0
Domain of the equation: 3p+5)!=0We get rid of parentheses
p∈R
-3p-2/3p-5+15=0
We multiply all the terms by the denominator
-3p*3p-5*3p+15*3p-2=0
Wy multiply elements
-9p^2-15p+45p-2=0
We add all the numbers together, and all the variables
-9p^2+30p-2=0
a = -9; b = 30; c = -2;
Δ = b2-4ac
Δ = 302-4·(-9)·(-2)
Δ = 828
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{828}=\sqrt{36*23}=\sqrt{36}*\sqrt{23}=6\sqrt{23}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6\sqrt{23}}{2*-9}=\frac{-30-6\sqrt{23}}{-18} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6\sqrt{23}}{2*-9}=\frac{-30+6\sqrt{23}}{-18} $
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