15-3(2x+1)=4(x-1)

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Solution for 15-3(2x+1)=4(x-1) equation: 



15-3(2x+1)=4(x-1)

We move all terms to the left:

15-3(2x+1)-(4(x-1))=0

We multiply parentheses

-6x-(4(x-1))-3+15=0



We calculate terms in parentheses: -(4(x-1)), so:

4(x-1)

We multiply parentheses

4x-4

Back to the equation:

-(4x-4)



We add all the numbers together, and all the variables

-6x-(4x-4)+12=0

We get rid of parentheses

-6x-4x+4+12=0

We add all the numbers together, and all the variables

-10x+16=0

We move all terms containing x to the left, all other terms to the right

-10x=-16

x=-16/-10

x=1+3/5

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