15-2(5-3)x=4(x-3)+13

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Solution for 15-2(5-3)x=4(x-3)+13 equation: 



15-2(5-3)x=4(x-3)+13

We move all terms to the left:

15-2(5-3)x-(4(x-3)+13)=0

We add all the numbers together, and all the variables

-22x-(4(x-3)+13)+15=0



We calculate terms in parentheses: -(4(x-3)+13), so:

4(x-3)+13

We multiply parentheses

4x-12+13

We add all the numbers together, and all the variables

4x+1

Back to the equation:

-(4x+1)



We get rid of parentheses

-22x-4x-1+15=0

We add all the numbers together, and all the variables

-26x+14=0

We move all terms containing x to the left, all other terms to the right

-26x=-14

x=-14/-26

x=7/13

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