15-(x+8)-2x=2(x-4)+2x-27

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Solution for 15-(x+8)-2x=2(x-4)+2x-27 equation: 



15-(x+8)-2x=2(x-4)+2x-27

We move all terms to the left:

15-(x+8)-2x-(2(x-4)+2x-27)=0

We add all the numbers together, and all the variables

-2x-(x+8)-(2(x-4)+2x-27)+15=0

We get rid of parentheses

-2x-x-(2(x-4)+2x-27)-8+15=0



We calculate terms in parentheses: -(2(x-4)+2x-27), so:

2(x-4)+2x-27

We add all the numbers together, and all the variables

2x+2(x-4)-27

We multiply parentheses

2x+2x-8-27

We add all the numbers together, and all the variables

4x-35

Back to the equation:

-(4x-35)



We add all the numbers together, and all the variables

-3x-(4x-35)+7=0

We get rid of parentheses

-3x-4x+35+7=0

We add all the numbers together, and all the variables

-7x+42=0

We move all terms containing x to the left, all other terms to the right

-7x=-42

x=-42/-7

x=+6

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