15-(x+1)=9-5(x+1)

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Solution for 15-(x+1)=9-5(x+1) equation: 



15-(x+1)=9-5(x+1)

We move all terms to the left:

15-(x+1)-(9-5(x+1))=0

We get rid of parentheses

-x-(9-5(x+1))-1+15=0



We calculate terms in parentheses: -(9-5(x+1)), so:

9-5(x+1)

determiningTheFunctionDomain
-5(x+1)+9

We multiply parentheses

-5x-5+9

We add all the numbers together, and all the variables

-5x+4

Back to the equation:

-(-5x+4)



We add all the numbers together, and all the variables

-1x-(-5x+4)+14=0

We get rid of parentheses

-1x+5x-4+14=0

We add all the numbers together, and all the variables

4x+10=0

We move all terms containing x to the left, all other terms to the right

4x=-10

x=-10/4

x=-2+1/2

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