15-(3x-1)=4(x+1)+3x

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Solution for 15-(3x-1)=4(x+1)+3x equation: 



15-(3x-1)=4(x+1)+3x

We move all terms to the left:

15-(3x-1)-(4(x+1)+3x)=0

We get rid of parentheses

-3x-(4(x+1)+3x)+1+15=0



We calculate terms in parentheses: -(4(x+1)+3x), so:

4(x+1)+3x

We add all the numbers together, and all the variables

3x+4(x+1)

We multiply parentheses

3x+4x+4

We add all the numbers together, and all the variables

7x+4

Back to the equation:

-(7x+4)



We add all the numbers together, and all the variables

-3x-(7x+4)+16=0

We get rid of parentheses

-3x-7x-4+16=0

We add all the numbers together, and all the variables

-10x+12=0

We move all terms containing x to the left, all other terms to the right

-10x=-12

x=-12/-10

x=1+1/5

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