15+5/2d=13/4d

Solution for 15+5/2d=13/4d equation:

15+5/2d=13/4d

We move all terms to the left:

15+5/2d-(13/4d)=0


Domain of the equation: 2d!=0

d!=0/2

d!=0

d∈R



Domain of the equation: 4d)!=0

d!=0/1

d!=0

d∈R


We add all the numbers together, and all the variables

5/2d-(+13/4d)+15=0

We get rid of parentheses

5/2d-13/4d+15=0

We calculate fractions


20d/8d^2+(-26d)/8d^2+15=0

We multiply all the terms by the denominator


20d+(-26d)+15*8d^2=0

Wy multiply elements

120d^2+20d+(-26d)=0

We get rid of parentheses

120d^2+20d-26d=0

We add all the numbers together, and all the variables

120d^2-6d=0

a = 120; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·120·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*120}=\frac{0}{240}
=0
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*120}=\frac{12}{240}
=1/20
$