15+4x+3x-11=9(x+1)-2

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Solution for 15+4x+3x-11=9(x+1)-2 equation: 



15+4x+3x-11=9(x+1)-2

We move all terms to the left:

15+4x+3x-11-(9(x+1)-2)=0

We add all the numbers together, and all the variables

7x-(9(x+1)-2)+4=0



We calculate terms in parentheses: -(9(x+1)-2), so:

9(x+1)-2

We multiply parentheses

9x+9-2

We add all the numbers together, and all the variables

9x+7

Back to the equation:

-(9x+7)



We get rid of parentheses

7x-9x-7+4=0

We add all the numbers together, and all the variables

-2x-3=0

We move all terms containing x to the left, all other terms to the right

-2x=3

x=3/-2

x=-1+1/2

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