15+3=6(-x+5)-42

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Solution for 15+3=6(-x+5)-42 equation: 



15+3=6(-x+5)-42

We move all terms to the left:

15+3-(6(-x+5)-42)=0

We add all the numbers together, and all the variables

-(6(-1x+5)-42)+15+3=0

We add all the numbers together, and all the variables

-(6(-1x+5)-42)+18=0



We calculate terms in parentheses: -(6(-1x+5)-42), so:

6(-1x+5)-42

We multiply parentheses

-6x+30-42

We add all the numbers together, and all the variables

-6x-12

Back to the equation:

-(-6x-12)



We get rid of parentheses

6x+12+18=0

We add all the numbers together, and all the variables

6x+30=0

We move all terms containing x to the left, all other terms to the right

6x=-30

x=-30/6

x=-5

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